2x^2-34^2=0

Solution for 2x^2-34^2=0 equation:

2x^2-34^2=0

We add all the numbers together, and all the variables

2x^2-1156=0

a = 2; b = 0; c = -1156;
Δ = b2-4ac
Δ = 02-4·2·(-1156)
Δ = 9248
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9248}=\sqrt{4624*2}=\sqrt{4624}*\sqrt{2}=68\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-68\sqrt{2}}{2*2}=\frac{0-68\sqrt{2}}{4}
=-\frac{68\sqrt{2}}{4}
=-17\sqrt{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+68\sqrt{2}}{2*2}=\frac{0+68\sqrt{2}}{4}
=\frac{68\sqrt{2}}{4}
=17\sqrt{2}
$